x^2+72x-2304=0

Solution for x^2+72x-2304=0 equation:

x^2+72x-2304=0

a = 1; b = 72; c = -2304;
Δ = b2-4ac
Δ = 722-4·1·(-2304)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-120}{2*1}=\frac{-192}{2}
=-96
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+120}{2*1}=\frac{48}{2}
=24
$